Question

x^2-12x+30=0

Answer 1

use x=-(-b)plus minus square root b square -4ac whole thing over 2a

Answer 2

This can be done completing the squares also since the b value is even.

Answer 3

\[x^2-12x=-30\]
Add \[\frac{1}{2} b^2\]
to both sides:
\[x^2-12x+36=-30+36\]
\[(x-6)^2=6\]
Take square root of both sides:
\[x-6=\pm\sqrt{6}\]
\[x=6\pm\sqrt{6}\]

Answer 4

You can confirm this by doing it out the long way using the quadratic equation.