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solve the following systems of equations y=x-3 4x+y=32
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simply substitute y=x-3 into the second equation
5x-3 = 32 --> 5x = 35 --> x=7
x=7 :P
4x+x-3=32 5x-3=32 add 3 on each side which gives u.... 5x=35 then divide by 5 on each side...which gives the answer i gave u be4... x=7 :p
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