Question

Train traveling on parrellel tracks in same direction. Train A at 60mph passes station at 11.15. Train B at 70mph passes same station at 11:27. At what time will train b catch up with train A.

Answer 1

60x+12=70x; 12=10x; x=12/10=1.2; train b will catch up in 1.2 mins

Answer 2

that's not right

Answer 3

60x+720=70x
720=10x
x=72 minutes

Answer 4

I got 72 minutes but it seems a very long time when it is only 12 minutes behind train a.

Answer 5

Nvm, I found my error

Answer 6

Train A= 60x+(12/60)*60 (it is because Train A is 12 minutes ahead --> 12 minutes is 12/60 hour)
Train B= 70x

60x+12=70x
12=10x
x=1.2 minutes

Answer 7

you were right, gj

Answer 8

so it is not 60(x+12)=70x its just 60x+12=70x;12=10x;x=12/10;1.2 minutes

Answer 9

yes, since we are working with unit hours, we have to use hour--> 12 minutes=12/60 hours

Answer 10

so will i add 12 minutes or 1.2 minutes

Answer 11

where?

Answer 12

since the train B will pass Train A in 1.2 minutes,
11:27 + 1.2

Answer 13

the question is when will train b catch up with train a. will you add 12minutes or 1.2 minutes to 11:27

Answer 14

http://www.wolframalpha.com/input/?i=11%3A27++%2B+1.2+minutes

Answer 15

ok thanks and have a great day.