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if (2x+1)( x-5) =2(x^2-1), what is the value of x?
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wouldn't 2(x^2-1) be distributed to 2x^2-2?
oops oh sorry
x = -3/9=-1/3
do you need work?????????
yes i didn't know to cancel the 2x^2 so your first answer got me on the right track
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\[2x^2-9x-5=2x^2-2\] \[-5+2=2x^2-2x^2+9x\] \[9x=-3\] \[x=-3/9\] \[x=-1/3\]
oh! i did not know what i meant by work thanks anyways
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