Question

can anyone help me integrate

x(x^2+1)^3

Answer 1

help

Answer 2

another u- sub
put
\[u=x^2+1\]
\[du=2xdx\] so integrate
\[\frac{1}{2}\int u^3 du\]

Answer 3

get
\[\frac{u^4}{8}=\frac{(x^2+1)^4}{8}\]

Answer 4

don't forget the stupid plus C

Answer 5

gracias

Answer 6

welcomas