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OpenStudy (anonymous):
49^(x)=√(7)^(2x+6) solve for x
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OpenStudy (anonymous):
A) x = 3 B) x = 1 C) x = –1 D) x = –3
OpenStudy (anonymous):
\[49=\sqrt{7}^4\] so put \[x=4(2x+6)\] and solve for x
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