Question

Factor.
2w^5-54w^2

Answer 1

2w^2(w^3-27)

Answer 2

not done yet

Answer 3

hmm.

Answer 4

you get
\[2w^2(w^3-27)\] but
\[w^3-27\] is the "difference of two cubes" so it factors as
\[w^3-27=(w-3)(w^2+3w+9)\]

Answer 5

good catch satteleite