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i need help with factoring 81x^6+24x^3y^3 (the answer is 3x^3(3x+2y)(9x^2-6xy+4y^2) )
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please?
first find the GCF of the two terms this is 3x^3 so we get 3x^3(27x^3 + 8y^3) now we use the identity x^3 + y^3 = ( x + y)( x^2 - xy + y^2) replace x by cube root of 27 x^3 and y by cube root of 8 y^3 which is 3x and 2y respectively and you'll obtain the answer you want
are you ok with that?
how would i find the cube root of 27x^3 and 8y^3
i've given you them 27 x^3 : cube rt 27 = 3 and of x^3 = x :- 3x
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thank you
when you say, "now we use the identity," what does that mean?
nevermind. i got it :)
well 27x^3 + 8y^3 is the sum of two cubes as is x^3 + y^3
oh ok - good
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