Question

What method would be best to solve this system of equations? (Addition, Subtraction, Subsitution) How would you solve it?
Please include steps, because I want to learn how to do this.

Answer 1

\[2x+4y=8\]\[y-3=x\]

Answer 2

Substitute x=y-3 into the top equation, i.e. Change 2x in the top eq to 2(y-3)

Answer 3

y-3=x
or x=y-3 -----(1)

put the value of x in eq (2)

i.e, 2x+4y=8
2(y-3) +4y=8
2y-6+4y=8
2y+4y=8+6
6y=14
y=14/6=7/3

put the value of y in eq (1)

x=y-3
x=7/3-3
x=7-9/3
x=-2/3

Answer 4

Thanks to you both, this really helped me see what I should do!