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What method would be best to solve this system of equations? (Addition, Subtraction, Subsitution) How would you solve it? Please include steps, because I want to learn how to do this.
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\[2x+4y=8\]\[y-3=x\]
Substitute x=y-3 into the top equation, i.e. Change 2x in the top eq to 2(y-3)
y-3=x or x=y-3 -----(1) put the value of x in eq (2) i.e, 2x+4y=8 2(y-3) +4y=8 2y-6+4y=8 2y+4y=8+6 6y=14 y=14/6=7/3 put the value of y in eq (1) x=y-3 x=7/3-3 x=7-9/3 x=-2/3
Thanks to you both, this really helped me see what I should do!
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