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OpenStudy (anonymous):
solve for x: (x+1)^2 (x-2)+(x+1)(x-2)^2=0
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myininaya (myininaya):
factor out (x-2)(x+1) (x-2)(x+1)[(x+1)+(x-2)]=0 (x-2)(x+1)(2x-1)=0
myininaya (myininaya):
x=2,x=-1,x=1/2
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