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solve 4+5e^(-x)=9......not understanding how someone got x=0....could someone please explain this to me.
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rearranging and cancelling e^-x = 1 -> ln e^-x = -x = ln 1 = 0
k?
im not 100% sure if i got it. but i do see how you got. it just might be how the problem is set up then what im use to.
the only awkward bit is taking the ln of both sides and seeing that ln 1 is 0.
yeah, i think i just got thrown off by this one problem. now that i am looking at how you got and the problem i can see it more.
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:-)
thank you
ur welcome.
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