Question

Solve teh following equation for "x"

2sqr(x) = x-3

Answer 1

square both sides get
\[4x=(x-3)^2\] expand the right hand side to get
\[4x=x^2-6x+9\] then put
\[x^2-10x+9=0\] and solve the resulting quadratic equation by factoring

Answer 2

then check your answers in the original equation and one will not work, because
\[2\sqrt{x}\] is positive, not negative