Question

50=68-20log(t+1)

Answer 1

\[50=68-20\log(t+1)\]
\[-18=-20\log(t-1)\]
\[.9=\log(t+1)\]

Answer 2

is this log base ten?

Answer 3

or log base e?

Answer 4

i dont know, this is just how the problem is shown

Answer 5

well if it is log base ten answer is
\[10^{.9}=t+1\]
\[t=10^{.9}-1\]

Answer 6

if its not shown isnt it normally 10?

Answer 7

because that is what i thought

Answer 8

well if it was e based then would that mean that it would be e^.9=t+1?