Question

\log_{2}(8x-6)=5

Answer 1

rewrite in equivalent exponential form
\[\log_b(x)=y\iff b^y=x\]

Answer 2

so your first step is write
\[2^5=8x-6\] then solve for x

Answer 3

you got this now right?

Answer 4

no am still confuss, to tell you the truth

Answer 5

is the answer x = -20.5

Answer 6

ok we got
\[2^5=8x-6\] so
\[32=8x-6\] add 6 get
\[38=8x\][ divide by 8 get
\[x=\frac{38}{8}=\frac{19}{4}\][