Question

simplify by removing factors of 1:
(m^2-1)/(m+1)^2

Answer 1

\[\large \frac{m^2-1}{(m+1)^2}\]



\[\large \frac{(m-1)(m+1)}{(m+1)(m+1)}\]



\[\large \frac{m-1}{m+1}\]
So \[\large \frac{m^2-1}{(m+1)^2}=\frac{m-1}{m+1}\]