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Mathematics 20 Online
OpenStudy (anonymous):

Square of 54 XD

OpenStudy (anonymous):

\[\sqrt{54}=\sqrt{9*6} = 3*\sqrt{6} \]

OpenStudy (anonymous):

do you mean square root of 54?

OpenStudy (anonymous):

got it confused star

OpenStudy (anonymous):

??????????/ , r u here

OpenStudy (anonymous):

thank you very much

OpenStudy (anonymous):

my pleasure

OpenStudy (anonymous):

how about this?

OpenStudy (anonymous):

(a-5)^2=81

OpenStudy (anonymous):

\[(a-b)^2 = a^2 + b^2 - 2ab \]

OpenStudy (anonymous):

now using this identity we have \[(a-5)^2 = a^2 + 5^2 - 2(a)(5) \]

OpenStudy (anonymous):

\[a^2 + 25 - 10a\]

OpenStudy (anonymous):

\[(a-5)^2=81\] \[a-5=9\] or \[a-5=-9\] \[a=14\] or \[a=-4\]

OpenStudy (anonymous):

this was how to expand it but now how to simplify it is following

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

\[(a-5)^2 = 81 \]

OpenStudy (anonymous):

how about this?

OpenStudy (anonymous):

now here we have : \[\sqrt{(a-5)^2}=\sqrt{81}\]

OpenStudy (anonymous):

hence , \[(a-5) = 9 \]

OpenStudy (anonymous):

hence \[(a = 9+5) \]

OpenStudy (anonymous):

or that what satelite told u

OpenStudy (anonymous):

@confused star you should have two answers

OpenStudy (anonymous):

yes

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