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Mathematics 7 Online
OpenStudy (anonymous):

Hey every one if you could help me on some questions today that would be just grate ok here is the first one Use the quadratic formula to solve the equation. 5x^2 - 6x - 8 = 0

OpenStudy (anonymous):

OpenStudy (anonymous):

Maybe i typed it wrong xD so c above

OpenStudy (anonymous):

Factorise it: \[(5x+4)(x-2)=0\]

OpenStudy (anonymous):

\[(-b \pm \sqrt{b^2-4ac})/2a\]

OpenStudy (anonymous):

mathematicalpro this is overkill

OpenStudy (anonymous):

Ummm (-b \pm \sqrt{b^2-4ac})/2a ... what?

OpenStudy (anonymous):

quadratic formula

OpenStudy (anonymous):

Ok Yes I got that, you wrote it all jacked up any way can you help with the question or how to salve or... no help

OpenStudy (anonymous):

ahhh then mathematicalpro is right

OpenStudy (anonymous):

ummm Typing forever?

OpenStudy (anonymous):

wish i could give -1 good answer xD jk Thanks for trying, I will be done will the test be the time you are done typing soo i am out

OpenStudy (anonymous):

where a=5,b=-6 and c=-8 \[(-(-6) \pm \sqrt{(-6)^2-[4*5*(-8)]})/2(5)\] \[(6\pm \sqrt{36+160})/10\] \[(6\pm \sqrt{196})/10\] \[(6+14)/10=20/10=2\] \[(6-14)/10=-8/10=-4/5\] so,\[2,(-4/5)\]

OpenStudy (anonymous):

r u on a test?????????

OpenStudy (anonymous):

No, just a pre test

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