Question

2x-3(4-x)=3+4(x-1)
Solve for X

Answer 1

Open the parentheses using the distribution law: \(x(y+z)=xy+xz\). This tells you how to handle expressions which combine products and sums. That's actually the challenging part here, expanding the parts \(-3(4-x)\) and \(3(x-1)\).

Then transpose all x to one side of the equations and constant numbers to another side.

Answer 2

So then the equation becomes 8x-12-2xsquared=3x-3+4x-4 ?

Answer 3

There won't be anything squared.

\(2x-3(4-x)=3+4(x-1)\)
\(2x-12+3x=3+4x-4\)
\(5x-12=-1+4x\)
\(5x-4x=-1+12\)
\(x=11\)