Question

Solve for x in the proportion 3 times x over the quantity 3 times x minus 36 equals negative 1 over x.

x = 3 and x = −4

x = −3 and x = 4

x = −3

x = −12

Answer 1

\[\frac{3x}{3x-36} = \frac{-1}{x}\]
\[\frac{3x}{3(x-12)} = \frac{-1}{x}\]
\[\frac{x}{x-12}=\frac{-1}{x}\]
cross-multiply
\[x^{2} =-(x-12)\]
set equal to 0
\[x^{2}+x-12 = 0\]
Factor
\[(x+4)(x-3) = 0\]

Answer 2

whick one is the answer im trying to finish this online class

Answer 3

what makes (x+4) = 0 ??
what makes (x-3) =0 ??