a rancher has 100 meters fo fencing to enclose two adjacent rectangular corrals ---approximate the dimensions such that the enclosed area will be 350 square meters (it also gives you the equations 4x+3y=100 and 2xy=A)
i got as far as A=(200x-8x^2)/3
I don't know where to go from that

Question

dumbcow · Answer

From there, substitute 350 for A
(200x -8x^2)/3 = 350
Multiply by 3 on both sides
200x -8x^2 = 1050
set equal to 0
-8x^2 +200x -1050 = 0
Divide equation by 2
-4x^2 +100x -525 = 0
solve using quadratic formula

anonymous · Answer

okay I get 7.5 adn 17.5 for x now how do i find y?

dumbcow · Answer

plug those values back into one of the original equations
--> 4(7.5) +3y = 100
--> 4(17.5) +3y = 100

anonymous · Answer

okay I got y= 10 and (70/3) but when you graph the equation you don't get the same answer how come?

dumbcow · Answer

oh because the graph is giving y-values that represent the Area, not the "y" dimensions

anonymous · Answer

oh okay thanks

anonymous · Answer

@marleythemongoose you forgot to multiply by 2

anonymous · Answer

I did. ;-) And was about to fix that. No need now. Well done.