Question

What is the equation of the line that passes through the point (2, 3) and is perpendicular to the line y = –x – 3

Answer 1

ok you are going to need the point slope formula which is

y-y1=m(x-x1)

so we know our m value or slope is going to be the recipical of -1 which is 1

y-3=1(x-2)
y=x+1

Answer 2

y-3= 1(0-2)

Answer 3

y=mx+b , m= 1 , (2,3)
3=1(2)+b
3=2+b
1=b

y=x+1

Answer 4

yint=1
y=x+1 (slope is positive because of negative recipricoal)