Question

log (x+3) = 1 - log x

Answer 1

x=2

Answer 2

\[\log(x+3)+\log(x)=1\]
\[\log(x(x+3))=1\]
\[x(x+3)=10\]
\[x^2+3x-10=0\] etc

Answer 3

the "etc" is
\[(x+5)(x-2)=0\] so
\[x=2\] because x cannot be 5 because you cannot take the log of a negative number