Question

find the vertex, line of symmetry, the maximum or minumum value of the quadratic funciton f(x)=-2x^2+2x+3

Answer 1

f'(x) = -4x + 2 = 2(-2x+1)

x= 1/2
y = 3.5 (7/2)

Answer 2

vertex = (1/2,7/2)
LoS = x = 1/2
max = y = 7/2

Answer 3

I have already posted the solution in your first thread devette

Answer 4

Sub x=1/2 into the eqn again raheen