Question

find and label the vertex and the line of symmetry of f(x)-1/2x^2

Answer 1

is it f(x)=(-1/2)x^2 ?

Answer 2

the genaeral formula of this parabola would be
x^2=-4a.y
----> x^2=-2y
the vertex is (0,0)
the line of symmetry is the x-axis , i.e y=0

Answer 3

well the coefficients are:
a = -1/2
b=0
c = 0

for line of symmetry
x = -b/2a = 0
y = (-1/2)*0 = 0
vertex: (0,0)

Answer 4

http://www.youtube.com/watch?v=ttKRX1Zy7LE