The area of a rectangular field is 160m^2 and its length is twice its width .Find the dimensions of the feild.

Question

anonymous · Answer

A=LxW 
L=2W 
160m^2= W x 2W 
160m^2= 2W^2 
160m^2/2 = 2W^2/2 
80m^2=W^2 
W=square root of 80 
W=8.944m 
L=2W 
L=2(8.944) 
L=17.89m 
CHECKING:
A=LxW 
160m^2=8.944m x 17.89m 
160m^2=159.99 or 160m^2

anonymous · Answer

$$A= 160m ^{2}$$
A= L x W

its length is twice its width
L = 2w

so write the equation...

A = L x W

160m^2 = (2W) W

160m^2/2 = 2W^2/2

80m^2 = W^2

8.944 = W

Solve for L or length

L = 2W

L = 2(8.944)

L = 17.89m

Check

160m^2=8.944m x 17.89m
 
160m^2=159.99 or 160m^2