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write the standard form or the equation of the line parallel to x-2y-6=0 and passing through (0,1)
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dont delete your posts please ....
parallel lines have the same equations; except for the constant is changed
x-2y-c = 0 ; just plug in the values for x and y from the point they give youto calibrate it for the new "c"
line parallel to the given line will have the same slope.. therefore m = 1/2 y=mx+b 1 = 1/2(0) + b => b= 1 Line is y = 1/2 x + 1
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