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solve: 2sin(3x)=1 on [-pi,pi] thx
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/2 so you get sin(3x)=1/2
now you can think of this as sin x = 1/2 which will be pi/6 but you have 3 theta so pi/6*3
sin(3x)=1/2 since sin(x)=1/2 at pi/6 and 5pi/6 3x=pi/18 and 3x=5pi/18
so your answers will be pi/18 and 5pi/18
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