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Mathematics 19 Online
OpenStudy (anonymous):

prove (17/32)^(0.1) < (1/3)^(0.9)

OpenStudy (jwt625):

it's wrong,it should be (17/32)^(0.1)>(1/3)^(0.9). first we know if x>0,y>0,x^10>y^10,then x>y; we know that 17/32>(1/3)^9,so (17/32)^(0.1)>(1/3)^(0.9).

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