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Mathematics 16 Online
OpenStudy (anonymous):

Please help solve for r.....w=Cr(-2), where -2 represents an exponent. Thanks.

OpenStudy (anonymous):

\[w=Cr^{-2}\] \[w=\frac{C}{r^2}\] is a start

OpenStudy (anonymous):

so \[r^2=\frac{C}{w}\] and therefore \[r=\pm\sqrt{\frac{C}{w}}\]

OpenStudy (saifoo.khan):

Online College!

OpenStudy (saifoo.khan):

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