Question

want some medals?..
log2(2m+4)−log2(m−1)=3

Answer 1

can i redeem them for valuable gifts?

Answer 2

i want some

Answer 3

\[\log_{2}(2m+4) - \log_{2}(m-1)=3\]

Answer 4

this time it is a subtraction so write
\[\log_2(\frac{2m+4}{m-1})\]=3\] then solve
\[\frac{2m+4}{m-1}=2^3\]

Answer 5

thats what it was

Answer 6

can i redeem them for valuable gifts?

Answer 7

lol@satllite : )

Answer 8

\[\log_{2}(2m+4)-\log_{2}(m-1)= 3\]
\[\frac{2m+4}{m-1}=8\]
2m+4=8m-8
6m=12
m=12/6=2