the flower garden in bay area park measures 24 meters by 30 meters. the garden is surrounded by a paved walk of uniform width. if the combined area of the paved walk and the garden is 1080m^2, what is the width of the walk?

Question

anonymous · Answer

are u there?

anonymous · Answer

24*30 + 2*x*24 + 2*x*30 - 4x^2 = 1082
You have to solve:
108*x - 4*x^2 = 1082-720
                        = 362

anonymous · Answer

AKA 4x^2-108x+362=0

anonymous · Answer

Furthermore: 4x^2-108x+362=0 <=> (2x-27)^2=367 <=> 2x-27=±√367 <=> 2x=27±√367 <=> x=(27±√367)/2

anonymous · Answer

Approximately:
x=23.08         AND          x=3.92

The width of the walkway is not the width of one of the sides, therefore the answer is the second one.
The paved walk is 3.92 meters wide.