Question

the flower garden in bay area park measures 24 meters by 30 meters. the garden is surrounded by a paved walk of uniform width. if the combined area of the paved walk and the garden is 1080m^2, what is the width of the walk?

Answer 1

are u there?

Answer 2

24*30 + 2*x*24 + 2*x*30 - 4x^2 = 1082
You have to solve:
108*x - 4*x^2 = 1082-720
= 362

Answer 3

AKA 4x^2-108x+362=0

Answer 4

Furthermore:
4x^2-108x+362=0
<=> (2x-27)^2=367
<=> 2x-27=±√367
<=> 2x=27±√367
<=> x=(27±√367)/2

Answer 5

Approximately:
x=23.08 AND x=3.92

The width of the walkway is not the width of one of the sides, therefore the answer is the second one.
The paved walk is 3.92 meters wide.