Question

How do I find the access of symmetry for a Parabola?

Answer 1

its the axis that the parabola is mirrored over

Answer 2

depending on the form of the equation there are a few clues as to how to spot it

Answer 3

y = (x-n)^2 +m ; the axis of symmetry is then x = n

y = ax^2 + bx + c ; the axis of symmetry is then x = -b/2a