Question

series from 1to infinity of 2/3^n
find if converges of diverges and what is sum?

Answer 1

2/3^n

Answer 2

you can do limit comparison of to 1/3^n

Answer 3

which will get you o wait

Answer 4

is it this
\[(\frac{2}{3})\]

Answer 5

^N

Answer 6

it is supposed to converge to 1

Answer 7

but i have no idea how to reach that

Answer 8

indeed but is it\[(2/3)\]

Answer 9

\[(2/3)^n\]

Answer 10

sorry goldeneye... this thing isn't working well

Answer 11

or is the n only on bottom

Answer 12

n is only at the bottom as 3^n