Question

How do you factor and solve quadratic equations?

Answer 1

http://www.youtube.com/watch?v=SDe-1lGeS0U

Answer 2

http://www.youtube.com/watch?v=1Pva-Iv43Nc&feature=relmfu

Answer 3

for ax^2+bx+c=0
\[x=(-b \pm \sqrt{b^2-4ac})/(2a), (b^2-4ac>0)\]