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Mathematics 8 Online
OpenStudy (anonymous):

what is the center and radius of the cirlce (x+3)^2+(y-2)^2=4

OpenStudy (anonymous):

center should be \((-3, 2)\)

OpenStudy (anonymous):

Radius 2

OpenStudy (anonymous):

All you have to do is to compare with \( (x-h)^2 + (y-k)^2 = r^2\)

OpenStudy (anonymous):

ok thankx

OpenStudy (anonymous):

Where \(r\) is the radius and \(h,k\) is center

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