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OpenStudy (anonymous):
find the nth term of the sequence 1,1/2,3,1/4,5,1/6,..............
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OpenStudy (dumbcow):
well when n is odd, a_n = n when n is even, a_n = 1/n or n^-1 \[a_{n} = n^{(-1)^{n-1}}\]
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