A furniture rental company charges a base rate plus a rate per day for an office furniture set. There are two available plans. The super saver plan charges $100 + $5 per day. The best deal plan charges $150+$3 per day.
How many days make the super saver plan more expensive than the best deal plan? SHOW ALGEBRAIC INEQUALITY

Question

A furniture rental company charges a base rate plus a rate per day for an office furniture set. There are two available plans. The super saver plan charges $100 + $5 per day. The best deal plan charges $150+$3 per day. 
How many days make the super saver plan more expensive than the best deal plan? SHOW ALGEBRAIC INEQUALITY

anonymous · Answer

Let x be the number of days you rent for. You want to know when$$Plan \ A > Plan\  B$$

anonymous · Answer

If Plan A = 100 + 5x  and Plan B = 150 + 3x. You plug in those expressions and solve the inequality.

anonymous · Answer

A=100+5x>150+3x 2x<50 ? x<25 x>25 Plan A is more expensive after the 25th day the 26th day ?

anonymous · Answer

You only change the direction of the inequality if you divide or multiply by 0.

anonymous · Answer

A=100+5x>150+3x 
2x>50 
 x>25
 x>25
 Plan A is more expensive after the 25th day the 26th day ?

anonymous · Answer

O k thanks I keep forgetting
I  need to know if I am writing it out correctly

anonymous · Answer

If x > 25 then the number of days you rented must be greater than 25.

anonymous · Answer

oops should that be 20?

anonymous · Answer

for plan a to be more expensive.

anonymous · Answer

LOL

anonymous · Answer

You wrote it correctly. Plan A is more expensive after the 25th day.

anonymous · Answer

and the 25 is right ? its not 20

anonymous · Answer

No. if 2x > 50 than x > 50/2 and 50/2 is 25