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1/(x+a)=[2/(x-1)]-[1/(x-a)] solve for x
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\[x = a^2\]
could you show steps to get answer
I could but the steps are quite long
could you start me off I was thinking you multiply each side by (x-1)(X-a) to get a common denominator
You have to multiply both sides by (x-a)(x+a) and (x-1)
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