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Mathematics 17 Online
OpenStudy (anonymous):

Solve t^2=169

OpenStudy (anonymous):

t = 13

OpenStudy (anonymous):

How do you know?

OpenStudy (anonymous):

t=sqrt 169 t=13

OpenStudy (anonymous):

o tnx

hero (hero):

t = + or - 13

hero (hero):

\[t = \pm 13\]

OpenStudy (anonymous):

no let us see this that the root of a number is both its negative and positive t^2=169 t=+ or - 13 the reason is that 13*13=169 and -13*-13=169

hero (hero):

Another "after the fact" response

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