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solve. 0.5x+3(is greater than or equal to)1.3x-6 the solution is {xIx__ __
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\[0.5x + 3 \ge 1.3x -6\]
i do add 100 to all correct?
\[1.3x -6 \le 0.5x + 3\]\[0.8x \le 9\]\[x \le \frac{9}{0.8}\]\[x \le 11.25\]
Im just lost in this class.
\[x|x \le 11.25\]
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are u doing online school? I can help where are u stuck?
im doing online college. My whole problem is retention.
Its my final that im working on and if I dont pass the final I fail
i have done this like 3-4 times.
come here, i will help you out and show u step by step. =)
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