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Mathematics 21 Online
OpenStudy (anonymous):

X^2 -4x-2=0 X=?

OpenStudy (anonymous):

have you learnt the quadratic equation x= +-b sqrt(b^2-4ac)/2bc

OpenStudy (anonymous):

yes we tried that and got some rediculous answer when the answer is 4. the back of the book says so

OpenStudy (anonymous):

r u sure

OpenStudy (anonymous):

becoz if u take 4 nd substitute it into the equation u will not get 0

OpenStudy (anonymous):

alright ill give you the actual equation

OpenStudy (anonymous):

\[\sqrt{2x+1}+1 = x\]

OpenStudy (anonymous):

when you solve it u will get 0=x^2-4x not x^2-4x-2=0

OpenStudy (anonymous):

i just realized that sorry for the confusion

OpenStudy (anonymous):

its ok

OpenStudy (anonymous):

so how do you solve thaat

OpenStudy (anonymous):

there 're 2 results on quadratic formula

OpenStudy (anonymous):

\[\sqrt{2x+1}\]+1=x

OpenStudy (anonymous):

what are they and how do you do them?

OpenStudy (anonymous):

im so confused?? i cant understand how you wrote that???

OpenStudy (anonymous):

sqrt(2x+1) +1=x

OpenStudy (anonymous):

sqrt(2x+1)= x-1

OpenStudy (anonymous):

2x+1 = (x-1)^2

OpenStudy (anonymous):

2x+1 = x^2-2x+1

OpenStudy (anonymous):

0=x^2-4x

OpenStudy (anonymous):

0= x(x-4)

OpenStudy (anonymous):

0/x= x-4

OpenStudy (anonymous):

0=x-4

OpenStudy (anonymous):

x=4

OpenStudy (anonymous):

oh i didnt know you were allowed to divide by x just to get rid of it

OpenStudy (anonymous):

u can

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