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OpenStudy (anonymous):
X^2 -4x-2=0 X=?
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OpenStudy (anonymous):
have you learnt the quadratic equation x= +-b sqrt(b^2-4ac)/2bc
OpenStudy (anonymous):
yes we tried that and got some rediculous answer when the answer is 4. the back of the book says so
OpenStudy (anonymous):
r u sure
OpenStudy (anonymous):
becoz if u take 4 nd substitute it into the equation u will not get 0
OpenStudy (anonymous):
alright ill give you the actual equation
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OpenStudy (anonymous):
\[\sqrt{2x+1}+1 = x\]
OpenStudy (anonymous):
when you solve it u will get 0=x^2-4x not x^2-4x-2=0
OpenStudy (anonymous):
i just realized that sorry for the confusion
OpenStudy (anonymous):
its ok
OpenStudy (anonymous):
so how do you solve thaat
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OpenStudy (anonymous):
there 're 2 results on quadratic formula
OpenStudy (anonymous):
\[\sqrt{2x+1}\]+1=x
OpenStudy (anonymous):
what are they and how do you do them?
OpenStudy (anonymous):
im so confused?? i cant understand how you wrote that???
OpenStudy (anonymous):
sqrt(2x+1) +1=x
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OpenStudy (anonymous):
sqrt(2x+1)= x-1
OpenStudy (anonymous):
2x+1 = (x-1)^2
OpenStudy (anonymous):
2x+1 = x^2-2x+1
OpenStudy (anonymous):
0=x^2-4x
OpenStudy (anonymous):
0= x(x-4)
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OpenStudy (anonymous):
0/x= x-4
OpenStudy (anonymous):
0=x-4
OpenStudy (anonymous):
x=4
OpenStudy (anonymous):
oh i didnt know you were allowed to divide by x just to get rid of it
OpenStudy (anonymous):
u can
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