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OpenStudy (anonymous):
Solve for x: 8^(5x-10)=(1/16)^(2x-7)
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OpenStudy (anonymous):
Can you explain how you got to that?
OpenStudy (anonymous):
u can do this
OpenStudy (anonymous):
2^3^(5x-10) = (2^-4)^(2x-7) since 8 =2^3 and 1/16= 2^-4
OpenStudy (anonymous):
so u get 2^15x-30 = 2^-8x+28
OpenStudy (anonymous):
now ur bases are the same so u only have to equate the indices
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OpenStudy (anonymous):
15x-30= -8x+28
OpenStudy (anonymous):
Ok.That makes sense. Thanks a lot.
OpenStudy (anonymous):
23x=58 x=2.52
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