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OpenStudy (anonymous):
What are the factors of 6a2 + 3ab + 10a + 5b? (2a + 5)(3a + b) (2a + b)(3a + 5) (6a + b)(a + 5) (6a + 5)(a + b)
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jimthompson5910 (jim_thompson5910):
6a^2 + 3ab + 10a + 5b 3a(2a + b) + 5(2a + b) (3a + 5)(2a + b) (2a + b)(3a + 5) So the answer is choice B
OpenStudy (anonymous):
(2a + b)(3a + 5), b
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