Question

How Do I Solve " -2x^2=4x-3 " ?

Answer 1

If u want to get less confuse, use the quadratic formua;

Answer 2

Formula.

Answer 3

Don't Remember It .

Answer 4

set it equal to zero first...................then plug in coefficients into following quadratic formula
\[x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}\]

Answer 5

So How Would I Set It Up ?

Answer 6

identify your coefficients, a is with x^2, b is with x, c is the constant

Answer 7

make sense? ...............whats a,b,c for this equation?

Answer 8

u would have to rearrange for it to become this way
\[ax^2+bx+c=0\]

Answer 9

Can You Show Me How Too Set It Up With The Numbers In Place ? And I'll Try Too Solve It MySelf .

Answer 10

compare -2x^2=4x-3 with
ax^2+bx+c=0
rearrange it to get
-2x^2-4x+3=0
and now let us do some substitution
a=-2
b=-4
c=3
i hope is now understood