How Do I Solve " -2x^2=4x-3 " ?

Question

saifoo.khan · Answer

If u want to get less confuse, use the quadratic formua;

saifoo.khan · Answer

Formula.

anonymous · Answer

Don't Remember It .

dumbcow · Answer

set it equal to zero first...................then plug in coefficients into following quadratic formula
$$x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$$

anonymous · Answer

So How Would I Set It Up ?

dumbcow · Answer

identify your coefficients, a is with x^2, b is with x, c is the constant

dumbcow · Answer

make sense? ...............whats a,b,c for this equation?

anonymous · Answer

u would have to rearrange for it to become this way
$$ax^2+bx+c=0$$

anonymous · Answer

Can You Show Me How Too Set It Up With The Numbers In Place ? And I'll Try Too Solve It MySelf .

anonymous · Answer

compare -2x^2=4x-3 with
ax^2+bx+c=0
rearrange it to get 
-2x^2-4x+3=0
and now let us do some substitution
a=-2
b=-4
c=3
i hope is now understood