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3^2+b^2=4^2 I ended up with b^2=7 b=sq rt 7
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+ or - sqrt()7
(-x)^2 = x^2 (x)^2 = x^2 + or - for those
yes u r absolutely correct keep it up : transpose 2^2 to right hand side b^2 = 4^2-3^22 \[b^2=4^2-3^2\] \[b^2=16-9\] or \[b^2=(4+3)(4-3)\] \[b^2=7\] \[b=sqrt7\]
got it
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a medal would be gr8 kylie
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