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I have this integeral, i wanna see i what i did was right
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\[\int\limits_{}^{}(2x-\left| x \right|)\]
so what i did was......
the limits of integration are from -2 to 2
what i did was: \[\int\limits_{-2}^{0} (2x+x)\] and \[\int\limits_{0}^{2} (2x-x)\]
That's correct.
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so the inside of both, repectively, would be 3x and x, thats all i woould hav eto integrat
Yes. Then you simply add both results.
alright thanks
hope you know what your talkiing about man, cause i dont wann get this wrong
Using symmetries ... \[\int\limits_{-2}^{2}(2x-|x|)dx=-2\int\limits_{0}^{2}xdx\]
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