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OpenStudy (anonymous):

I have this integeral, i wanna see i what i did was right

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OpenStudy (anonymous):

\[\int\limits_{}^{}(2x-\left| x \right|)\]

OpenStudy (anonymous):

so what i did was......

OpenStudy (anonymous):

the limits of integration are from -2 to 2

OpenStudy (anonymous):

what i did was: \[\int\limits_{-2}^{0} (2x+x)\] and \[\int\limits_{0}^{2} (2x-x)\]

OpenStudy (anonymous):

That's correct.

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OpenStudy (anonymous):

so the inside of both, repectively, would be 3x and x, thats all i woould hav eto integrat

OpenStudy (anonymous):

Yes. Then you simply add both results.

OpenStudy (anonymous):

alright thanks

OpenStudy (anonymous):

hope you know what your talkiing about man, cause i dont wann get this wrong

OpenStudy (zarkon):

Using symmetries ... \[\int\limits_{-2}^{2}(2x-|x|)dx=-2\int\limits_{0}^{2}xdx\]

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