Question

I have this integeral, i wanna see i what i did was right

Answer 1

\[\int\limits_{}^{}(2x-\left| x \right|)\]

Answer 2

so what i did was......

Answer 3

the limits of integration are from -2 to 2

Answer 4

what i did was:

\[\int\limits_{-2}^{0} (2x+x)\]

and


\[\int\limits_{0}^{2} (2x-x)\]

Answer 5

That's correct.

Answer 6

so the inside of both, repectively, would be 3x and x, thats all i woould hav eto integrat

Answer 7

Yes. Then you simply add both results.

Answer 8

alright thanks

Answer 9

hope you know what your talkiing about man, cause i dont wann get this wrong

Answer 10

Using symmetries ...

\[\int\limits_{-2}^{2}(2x-|x|)dx=-2\int\limits_{0}^{2}xdx\]