OpenStudy (anonymous):

Expand as a binomial series and simplify: (x+3)^7

6 years ago
OpenStudy (anonymous):

I got \[x ^{7} +21x ^{6}+189x ^{5}+945x ^{4}+2835x ^{3}+5103^{2}+5103x+2187\]I haven't worked with these before, so I was wondering if someone could check my work.

6 years ago
OpenStudy (anonymous):

http://www.wolframalpha.com/input/?i=%28x%2B3%29^7

6 years ago
OpenStudy (anonymous):

Interestingly 2187 is 3^7

6 years ago
OpenStudy (jim_thompson5910):

You have the correct answer. Good job.

6 years ago
OpenStudy (jim_thompson5910):

assuming you meant \[5103x^{2}\]

6 years ago
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