Question

(square root of 2)+x)(square root of 8)-x)

Answer 1

Foil it out.

Answer 2

i dont no how to foil it

Answer 3

i dont no how to foil it

Answer 4

is the answer 4+2 times the square root of x -x^2

Answer 5

\[(\sqrt{2} + x)(\sqrt{8} -x)\]\[=(\sqrt{2})(\sqrt{8})\ \ + \ \ (\sqrt{8})x \ + \ \ \ (\sqrt{2})(-x)\ \ \ \ +\ \ \ (x)(-x)\] ^First terms ^Inner terms ^Outer terms ^Last terms

Answer 6

i dont no how to foil it

Answer 7

i no how to do that part but i dont no how multiply square roots by a normal number

Answer 8

Then you multiply them.
\[\sqrt{2}\sqrt{8} = \sqrt{2\cdot 8} = \sqrt{16} = 4\]
\[\sqrt{8} = \sqrt{4\cdot 2} = 2\sqrt{2}\]\[\implies \sqrt{8}x - \sqrt{2}x = 2\sqrt{2}x - \sqrt{2}x = \sqrt{2}x\]
\[x\cdot -x = -x^2\]

Answer 9

i dont no how to foil it

Answer 10

so wats the answer

Answer 11

I showed you how to foil it, and gave you the solution.

Answer 12

i dont no how to foil it

Answer 13

im sorry i dont understand

Answer 14

To foil it, you sum the product of the First terms, the inner terms, the outer terms, and the last terms.

Answer 15

i dont no how to foil it

Answer 16

\[i got up \to 4-\sqrt{2x}+2\sqrt{2x}x^{2}\]

Answer 17

i dont no how to foil it

Answer 18

sorry minus x^2 at the end

Answer 19

Ok so now from the two middle terms you can factor out a \((\sqrt{2})x\)

Answer 20

sry idk wat ur tellin me 2 do is this it
\[ 4-2x \times 2-x^{2}\]

Answer 21

Nope

Answer 22

i dont no how to foil it

Answer 23

sry lol

Answer 24

Ok, lets see here.

Answer 25

Let's ignore the first and last terms They're 4 and -x^2. You have those right

Answer 26

So all we care about for now is this:
\[(2\sqrt{2})x - (\sqrt{2})x\]

Answer 27

Right?

Answer 28

yep

Answer 29

Ok lets try this:\[\]2ab - ab\[\]What is that the same as?

Answer 30

Not sure?

Answer 31

i dont no how to foil it

Answer 32

idk is it \[2\sqrt{2x}-2x\]

Answer 33

Hrm. Maybe this will work better.\[\]Let \(\sqrt{2}x = oranges\)\[\]Therefore \[2(\sqrt{2}x) - \sqrt{2}x\]\[=2(\sqrt{2}x) - 1(\sqrt{2}x)\]\[=2oranges - 1oranges\]\[= ?\]

Answer 34

i dont no how to foil it

Answer 35

1 orange

Answer 36

Right!

Answer 37

And what is oranges again (we defined it above)

Answer 38

i dont no how to foil it

Answer 39

square root of 2x

Answer 40

(sqrt 2)x

Answer 41

But yes

Answer 42

So therefore\[2(\sqrt{2})x - 1(\sqrt{2})x = 1(\sqrt{2})x\]

Answer 43

i dont no how to foil it

Answer 44

omg yes it does!!!!!

Answer 45

So that's the form of the middle term

Answer 46

is that it were the outside terms correct

Answer 47

Now we put back in your first and last terms, and we have:
\[4 + 2(\sqrt{2})x - (\sqrt{2})x - x^2\]\[=4 + (\sqrt{2})x - x^2\]

Answer 48

i dont no how to foil it

Answer 49

thnx soooooooooo much ur like a genius

Answer 50

Just takes practice. Nothing special about me ;P

Answer 51

Happy to help though

Answer 52

alright well thnx 4 the help but i gtg and do more math

Answer 53

Have fun =)