OpenStudy (anonymous):

I cant figure this out... ive tried 3 times.... Amir pitched a baseball at an initial height of 5.9 feet with a velocity of 73.16 feet per second. About how long will it take the ball Amir pitched to hit the ground?

6 years ago
OpenStudy (anonymous):

No wait.... i think i got it. Is it 4.66 sec?

6 years ago
OpenStudy (anonymous):

Did you break it down to it's horizontal and vertical components?

6 years ago
OpenStudy (anonymous):

I think i did. Sorry, im not very good at math haha :) But yea, I broke it down and used this equation H(t) = –16t^2 + vt + s

6 years ago
OpenStudy (dumbcow):

height function: h(t) = -16t^2+Vy*t + 5.9....where Vy is initial velocity in vertical direction........Vy = -73.16*sin(theta)....

6 years ago
OpenStudy (dumbcow):

is there any other info? we need to know the angle the ball is thrown

6 years ago
OpenStudy (anonymous):

no... all i have are the possible answers, here 1). 4.66 secs 2). 2.94 secs 3). 2.35 secs 4). 1.47 secs

6 years ago
OpenStudy (anonymous):

I think this is just a simple projectile question that doesn't require angles

6 years ago
OpenStudy (anonymous):

Is the initial velocity 73.16 the horizontal or vertical or does it make you assume?

6 years ago
OpenStudy (anonymous):

it makes u assume

6 years ago
OpenStudy (dumbcow):

it can't be vertical or else you get .079 sec

6 years ago
OpenStudy (dumbcow):

wow i am over thinking this...haha h(t) = -16t^2 +73.16t +5.9 = 0..........t = 4.65

6 years ago
OpenStudy (anonymous):

Oh jeez. LOL ^ That's right... -face/palm-

6 years ago
OpenStudy (dumbcow):

Artistic, you were right all along.....don't mind us :)

6 years ago
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