I cant figure this out... ive tried 3 times.... Amir pitched a baseball at an initial height of 5.9 feet with a velocity of 73.16 feet per second. About how long will it take the ball Amir pitched to hit the ground?

No wait.... i think i got it. Is it 4.66 sec?

Did you break it down to it's horizontal and vertical components?

I think i did. Sorry, im not very good at math haha :) But yea, I broke it down and used this equation H(t) = –16t^2 + vt + s

height function: h(t) = -16t^2+Vy*t + 5.9....where Vy is initial velocity in vertical direction........Vy = -73.16*sin(theta)....

is there any other info? we need to know the angle the ball is thrown

no... all i have are the possible answers, here 1). 4.66 secs 2). 2.94 secs 3). 2.35 secs 4). 1.47 secs

I think this is just a simple projectile question that doesn't require angles

Is the initial velocity 73.16 the horizontal or vertical or does it make you assume?

it makes u assume

it can't be vertical or else you get .079 sec

wow i am over thinking this...haha h(t) = -16t^2 +73.16t +5.9 = 0..........t = 4.65

Oh jeez. LOL ^ That's right... -face/palm-

Artistic, you were right all along.....don't mind us :)

Join our real-time social learning platform and learn together with your friends!