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3^(x^2) = 9^(5x-8) I get stumped after I get it down to (x^2) = 10x -16
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oh right you did the getting out of the exponent part.
now solve \[x^2=10x-16\] \[x^2-10x+16=0\] etc
you did the hard part correctly. now you have a quadratic to solve. this factors even as \[(x-2)(x-8)=0\] and so on
Thank you!! Well the answer stays in the quadratic right??
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